[백준] 브론즈2-트럭 주차 C++ 2979번

https://www.acmicpc.net/problem/2979

 

// 시각은 [이상, 미만) 범위다.

#include <iostream>
using namespace std;

int A, B, C, sum;
int cnt[100];

int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);

	cin >> A >> B >> C;
	for (int i = 0; i < 3; i++)
	{
		int start, end;
		cin >> start >> end;
		for (int j = start; j < end; j++)
			cnt[j]++;
	}

	for (int i = 0; i < 100; i++)
	{
		if (cnt[i])
		{
			if (cnt[i] == 1)
			{
				sum += A;
			}
			else if (cnt[i] == 2)
			{
				sum += B * 2;
			}
			else if (cnt[i] == 3)
			{
				sum += C * 3;
			}
		}
	}
	cout << sum << '\n';

	return 0;
}

// 2회차 풀이
#include <iostream>
using namespace std;

int a, b, c;
int arr[102];
int sum;

int main()
{
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);

	cin >> a >> b >> c;

	for (int i = 0; i < 3; i++)
	{
		int x, y;
		cin >> x >> y;
		for (int j = x; j < y; j++)
		{
			arr[j]++;
		}
	}

	for (int i = 1; i <= 100; i++)
	{
		if (arr[i] == 0) continue;
		else if (arr[i] == 1)
			sum += a;
		else if (arr[i] == 2)
			sum += b * 2;
		else if (arr[i] == 3)
			sum += c * 3;
	}

	cout << sum;

	return 0;
}